Hello there.

Havent been on here for a while.

Hope everyone is well?

You will be pleased to hear I have now grown up and am not a silly little boy.

But I still expect the piss-taking so...

 

Anyway. I saw this question on another forum. See if any of you lot can do it

 

So, you are on a train. The train is travelling north at a velocity of 50mph.

 

You are in the first class carriage, in which there is an escalator moving in the opposite direction (south) moving at a velocityof 6mph. The escalator is angled at 45 degrees.

 

You, being the messer that you are, are running in the opposite direction on the escalator at a velocity of 8mph.

 

So, what direction are you moving, in relation to the ground, and at what velocity taking all factors into account?

 

Answers after I have been training

If you want a serious answer Rich, you're wasting your time.

 

Work it out for yourself, using this as a clue.

If you're on a train travelling 100mph and you jump up in the air, why do you still land on the same spot?

Dont take much but i lost?

 

Answer anyone.

Oh I know the answer already. Its relatively simple.

But im still trying to work out why you would land on the same spot... I cant see how that is possible?

 

 

because E=MC/2 obvious really

Edited January 17, 200818 yr by fatolive

but then how come your image in a mirror is swapped over left to right but not up to down?

Dont take much but i lost?

 

Answer anyone.

 

Because you are travelling at a 100mph as well.

 

Think of it like this - when you get in your car you put your seat belt on. If you have a crash, the seat belt saves you from flying through the windscreen - that is because when you crash your car it decelerates in an instant from the speed you were travelling (say 60mph) to zero. If you did not have your belt on and the car crashed then although it had stopped dead - you have not and so you would fly forward still travelling at 60mph into the windscreen!

 

So if you jumped up on the train - the train is moving at 100mph - you are moving at 100mph - and hence you will land on the same spot you took off from.

 

In reply to Rich's original question you would be travelling in the same direction and at the same speed that the train is travelling - hence Traf's reply above.

but then how come your image in a mirror is swapped over left to right but not up to down?

because i look bad enough in it as it is

Because you are travelling at a 100mph as well.

 

Think of it like this - when you get in your car you put your seat belt on. If you have a crash, the seat belt saves you from flying through the windscreen - that is because when you crash your car it decelerates in an instant from the speed you were travelling (say 60mph) to zero. If you did not have your belt on and the car crashed then although it had stopped dead - you have not and so you would fly forward still travelling at 60mph into the windscreen!

 

So if you jumped up on the train - the train is moving at 100mph - you are moving at 100mph - and hence you will land on the same spot you took off from.

 

In reply to Rich's original question you would be travelling in the same direction and at the same speed that the train is travelling - hence Traf's reply above.

Got yer.

but then how come your image in a mirror is swapped over left to right but not up to down?

 

Because your image is not 'swapped over' merely reflected - thus nothing as changed just that the 'reflection' portrays to yourself how everyone else actually sees you!

But surely air resistance would push you back when in the air?

But surely air resistance would push you back when in the air?

the air is moving as well

Because your image is not 'swapped over' merely reflected - thus nothing as changed just that the 'reflection' portrays to yourself how everyone else actually sees you!

well in that case how come the distance from your elbow to your wrist is identical to the distance from the back of your foot to the end of your toes. eh?

Three men go to a hotel room to stay. They receive a bill for ?30 and so each gives ?10 to the porter, who takes the dosh to the till. The hotel manager informs the poter that the bill should only have been for ?25 and returns ?5 to the porter in pound coins . On the way back to the room the porter remembers that they didn't give him a tip and so bungs each one of them a quid and pockets the other two quid for himself.

Now that each man has been given a quid refund, each of the them has paid ?9. Three times 9 is 27. The porter has 2 quid in his pocket. Two plus 27 is ?29. The men originally handed over ?30. Where is the missing quid?

well in that case how come the distance from your elbow to your wrist is identical to the distance from the back of your foot to the end of your toes. eh?

on the subject of mysterious questions, i'm sure last night pablo posted a topic listing evertons firsts etc, youre shite i think it was called, a good few replies calling him a scouse red ginger etc, now it doesnt seem to be anywhere, wheres it gone?

well in that case how come the distance from your elbow to your wrist is identical to the distance from the back of your foot to the end of your toes. eh?

Holy shit. How you lot know all this.

Edited January 17, 200818 yr by M G WHITES

well in that case how come the distance from your elbow to your wrist is identical to the distance from the back of your foot to the end of your toes. eh?

 

Because I don't believe that to be true. There may well be a similarity in the size of both but in many cases they will not be identical.

 

Dr Sluffy MD.

In reply to Rich's original question you would be travelling in the same direction and at the same speed that the train is travelling - hence Traf's reply above.

 

You wouldnt. You would be travelling at 51.414 mph.

Its all relative to the ground.

50mph that the train is travelling at.

And then 1.414.....mph that you are travelling at along the horizontal.

Now then Rich, your task is to calculate how many people were well aware of that all along

You wouldnt. You would be travelling at 51.414 mph.

Its all relative to the ground.

50mph that the train is travelling at.

And then 1.414.....mph that you are travelling at along the horizontal.

 

Yes, you are spot on Rich - I was really only trying to show that the speed of the train in which you were travelling was the most significant part of the question.

 

If anyone really wants to know how the 1.414mph is derived -

 

It is because you are travelling in a north direction at 2mph (8mph - 6mp) at a 45 degree angle.

 

Because you are travelling in a 45 degree angle you are not travelling 2mph in a horizontal way but sort of like travelling into the ground - so how then do you work out how far you would have travelled along the ground (rather than 'into' the ground - if you understand what I mean.

 

The answer is by Pythagoras theorem - being 'The square on the hypotenuse is equal to the sum of the squares on the other two sides'.

 

In this case the hypotenuse is the 2 miles you would have travelled in the hour.

 

Because the hypotenuse is stated to be 45 degrees it is easy to construct a right handed triangle (a 90 degree triangle with both the other two internal angles being 45 degree's each - total internal degrees of a triangle adding up to 180 degrees).

 

A you know the hypotenuse is 2 miles long then the area of its square would be 4 square miles (2 miles x 2 miles).

 

Thus the squares on the other two sides must (when added together) total 4 square miles.

 

Therefore you must have two squares each with sides of 1.414 miles - (1.414 x 1.414 = 1.999 miles which is rounded up to two square miles. - 2 square miles plus another 2 square miles = 4 square miles - the same as the square on the hypotenuse.

 

Therefore the person would be travelling 1.414 miles if he was travelling along the horizon plus the 50 miles per hour he is travelling on the train - thus the right answer is indeed 51.414mph in a north direction.

 

Easy!

Yes, you are spot on Rich - I was really only trying to show that the speed of the train in which you were travelling was the most significant part of the question.

 

If anyone really wants to know how the 1.414mph is derived -

 

It is because you are travelling in a north direction at 2mph (8mph - 6mp) at a 45 degree angle.

 

Because you are travelling in a 45 degree angle you are not travelling 2mph in a horizontal way but sort of like travelling into the ground - so how then do you work out how far you would have travelled along the ground (rather than 'into' the ground - if you understand what I mean.

 

The answer is by Pythagoras theorem - being 'The square on the hypotenuse is equal to the sum of the squares on the other two sides'.

 

In this case the hypotenuse is the 2 miles you would have travelled in the hour.

 

Because the hypotenuse is stated to be 45 degrees it is easy to construct a right handed triangle (a 90 degree triangle with both the other two internal angles being 45 degree's each - total internal degrees of a triangle adding up to 180 degrees).

 

A you know the hypotenuse is 2 miles long then the area of its square would be 4 square miles (2 miles x 2 miles).

 

Thus the squares on the other two sides must (when added together) total 4 square miles.

 

Therefore you must have two squares each with sides of 1.414 miles - (1.414 x 1.414 = 1.999 miles which is rounded up to two square miles. - 2 square miles plus another 2 square miles = 4 square miles - the same as the square on the hypotenuse.

 

Therefore the person would be travelling 1.414 miles if he was travelling along the horizon plus the 50 miles per hour he is travelling on the train - thus the right answer is indeed 51.414mph in a north direction.

 

Easy!

ah i see, so the quid from the hotel is on the train ,get it now.

Edited January 17, 200818 yr by fatolive

Three men go to a hotel room to stay. They receive a bill for ?30 and so each gives ?10 to the porter, who takes the dosh to the till. The hotel manager informs the poter that the bill should only have been for ?25 and returns ?5 to the porter in pound coins . On the way back to the room the porter remembers that they didn't give him a tip and so bungs each one of them a quid and pockets the other two quid for himself.

Now that each man has been given a quid refund, each of the them has paid ?9. Three times 9 is 27. The porter has 2 quid in his pocket. Two plus 27 is ?29. The men originally handed over ?30. Where is the missing quid?

 

The missing quid was never there in the first place!

 

This is one of those questions that you have to concentrate on the 'direction' of the question - as it reads ok in one way - and it reads ok the other way - but the two ways seem to not agree when put side by side!

 

Let me give you an example - we all know that (counting thumbs as fingers) that we have 5 fingers on each hand and ten in total.

 

Ok to prove this just hold your hands up - and count them out aloud 1,2,3.4,5 on your right hand - then continue 6,7,8,9 and 10 on your left hand - all there good! BUT now count backwards - 10,9,8,7,6 on your left hand - PLUS the 5 you have still to count on your right hand - just a minute 6 plus 5 = 11 fingers - that can't be right can it!

 

Similarly with the three men and the porter.

 

Concentrate on what it cost the men in total - ?25 for the room and ?2 tip = ?27

They gave the porter ?30 and got ?3 change =?27 the same cost - ok

 

Therefore the 'missing' pound is just like the 'eleventh finger' - it never existed - it was simply the way that the question was asked!

Edited January 17, 200818 yr by Sluffy

Aye thats it sluffy but I worked it out using cos(theta) = Adjacent/Hypotenuse.

And then coming out with 1.41421356.

Both ways are just as good.

And Satan, I guess possibly not many...

Aye thats it sluffy but I worked it out using cos(theta) = Adjacent/Hypotenuse.

And then coming out with 1.41421356.

Both ways are just as good.

And Satan, I guess possibly not many...

 

Dick

 

Are you under the impression that you are posting on a Carol Voderman forum?

Dick

 

Are you under the impression that you are posting on a Carol Voderman forum?

 

Have a gander at that Widnes:

http://forums.superiorpics.com/ubbthreads/...680/an/0/page/0

 

There's some odd types on this 'ere interweb.

Aye thats it sluffy but I worked it out using cos(theta) = Adjacent/Hypotenuse.

And then coming out with 1.41421356.

Both ways are just as good.

And Satan, I guess possibly not many...

 

 

I bet you can't lick your elbow!

And Satan, I guess possibly not many...

Why would you say that then? Seriously, why? Do you think that just because you can do an O Level maths question you're empowered with some arcane knowledge lost on the rest of humanity? Granted, Squidgy and Skin are thick as f?ck, and Undies thinks he has a ghost in his loft, but apart from them you might not want to jump to conclusions.

Why would you say that then? Seriously, why? Do you think that just because you can do an O Level maths question you're empowered with some arcane knowledge lost on the rest of humanity? Granted, Squidgy and Skin are thick as f?ck, and Undies thinks he has a ghost in his loft, but apart from them you might not want to jump to conclusions.

 

Fair enough mate. Maybe I was wrong. Sorry.

But all the silly questions suggested otherwise...